Answer:
a) 77 degrees Celsius
bi) 40.45066 degrees Celsius
bii) 24.0764 degree Celsius
Explanation:
I'm assuming the temperature function is:
.
a) The initial temperature can be found by replacing t with 0.
![T(0)=55(0.913)^0+22](https://img.qammunity.org/2020/formulas/mathematics/middle-school/20lx1bamrwa7plgitwmxmtvvtzls1gmpaw.png)
![T(0)=55(1)+22](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1u3q7mycavew93ywvifobm2j9143k7x8h9.png)
![T(0)=55+22](https://img.qammunity.org/2020/formulas/mathematics/middle-school/egjqtzcv2463qdy3asi03xzenw6406jywx.png)
![T(0)=77](https://img.qammunity.org/2020/formulas/mathematics/middle-school/t3ewg4uuyeuw6zhfhs9kb4ychx2eqfqu7z.png)
bi) We are to replace t with 12:
![T(12)=55(0.913)^(12)+22](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qb1gqnnomlp4laxdtz304jtvi6ffdbb1yi.png)
Just put right hand side into the calculator as:
55*(0.913)^12+22 which should output 40.45066 approximately.
bii) We are to replace t with 36:
![T(36)=55(0.913)^(36)+22](https://img.qammunity.org/2020/formulas/mathematics/middle-school/sudwa6s9mogd4f8piywilsh7v8hqkw6u32.png)
Putting right hand side into calculator as 55*(0.913)^36+22 gives:
24.0764 approximately.