Question

Find the number of real number solutions for the equation x^2-6=0

Answer 1

Explanation:

x^2-6=0

x^+6=0 ( add six to both sides)

x^2=6

x= the square root of 6 ( to get rid of the exponent you have to do the opposite....which is the square root)

x=2.44948974278

You may have to round if not given the exact number.

Answer 2

`x=√(6)` and
`x=-√(6)`

Explanation:

We have the following quadratic equation

`x^2-6=0`

To solve the equation add 6 to both sides of the equality

`x^2-6+6=6`

`x^2=6`

Now apply the square root function on both sides of the equation

`√(x^2)=√(6)`

`x=\±√(6)`

This means that the solutions are:

`x=√(6)` and
`x=-√(6)`