Question

What is an equation of the line that passes through (0, 8) and (4, 0)?

y = -2x + 4
y = 2x + 4
y = -2x + 8
y = 2x + 8

Answer 1

y= -2x+8

Explanation:

the equation of the line:

y = mx+b

m=slope=(y2-y1)/(x2-x1)

we have: (0,8) and (4,0)

we will find the slope:

m=(0-8)/4-0)

m=-8/4 = -2

using the point (0,8) we will find "b"

8 = -2(0)+b

b=8

so the equation is: y=-2x+8