Answer:
(a) The z-critical value for a left-tailed test, for a significance level of α=0.05 is -1.64.
(b) Since -1.54 > -1.64, therefore we accept H₀.
Explanation:
(a)
It is given that the value of test statistic is
![z=-1.54](https://img.qammunity.org/2020/formulas/mathematics/college/8iu9szkhs8bsrqupfdctvoakaeoj6qbbvm.png)
We need to test the claim that p<0.18.
Null hypothesis:
![H_0:p=0.18](https://img.qammunity.org/2020/formulas/mathematics/college/xbaz7d29k4fhnm4mb6umuqv4df1dz4zm1q.png)
Alternative hypothesis:
![H_1:p<0.18](https://img.qammunity.org/2020/formulas/mathematics/college/krb93d6irlctun85u80z28e12o6dvfilju.png)
It is a left tailed test.
Significance level:
![\alpha=0.05](https://img.qammunity.org/2020/formulas/mathematics/college/o3op132eurfz836qnoznjuckj0omh3ecx4.png)
The z-critical value for a left-tailed test, for a significance level of α=0.05 is -1.64.
(b)
It is a left tailed test and critical value is -1.64 it means the region on left of -1.64 is rejection region.
The value of z is -1.54 and the critical value is -1.64.
We know that -1.54 > -1.64.
Therefore we accept H₀.