Answer:
Explanation:
Given that a researcher is conducting a chi-square test for independence to evaluate the relationship between gender and preference for three different designs for a new automobile.
Thus we have gender divided into two rows and 3 designs into 3 columns
i.e.

So degree of freedom

Chi square = 4.81
p value = 0.090265
If significance level of 5% is taken then we hae
p value >0.05
Hence accept null hypothesis that there is independence between gender and designs