Answer:
Explanation:
Given that a researcher is conducting a chi-square test for independence to evaluate the relationship between gender and preference for three different designs for a new automobile.
Thus we have gender divided into two rows and 3 designs into 3 columns
i.e.
![r=2 and c = 3](https://img.qammunity.org/2020/formulas/mathematics/college/67kf26prf5dujc0144kew47edgqlx5tun5.png)
So degree of freedom
![= (r-1)(c-1)\\=2](https://img.qammunity.org/2020/formulas/mathematics/college/qx59l1rrmd6jabnd3kuq83sybyutmyzqyl.png)
Chi square = 4.81
p value = 0.090265
If significance level of 5% is taken then we hae
p value >0.05
Hence accept null hypothesis that there is independence between gender and designs