Answer: First Option
![Z<-1.33](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bxwhupnqdloyo11794oswu0rbyr0przncl.png)
Explanation:
We know that the mean is:
![\mu=29\ minutes](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2wupa9g9i350butr4f5xjmx7ejyyau05vq.png)
We know that the standard deviation is:
![\sigma=3\ minutes](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4d3es1nb0biro4u70ti6y8jk2mh2cm0cvo.png)
The formula to calculate the Z-scores is:
![Z=(X-\mu)/(\sigma)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/i2xg594oqinedon5dql2sxwrrj7frkqj0s.png)
Where in this case
![X=25\ minutes](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jndybw6naa2afm7xkprgz6o330b3jnszvx.png)
Then the z-score for
is:
![Z=(25-29)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/w7vhatqaiuyny66in118rx674i5ynic2ia.png)
![Z=-(4)/(3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2lybj1ecuzcl4qmu32vhjijrlm4oxneqv6.png)
The negative number means that the deviation is to the left of the mean. In other words 25minutes is at 1.33 standard deviations to the left of the mean
![Z<-1.33](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bxwhupnqdloyo11794oswu0rbyr0przncl.png)