Question

A dog kennel owner has 147ft. of fencing to enclose a rectangular dog run. She wants it to be 6times as long as it is wide. Find the dimensions

Answer 1

63 feet long and 10.5 feet wide

Explanation:

147 is the maximum amount of fencing, which means that this is dealing with perimeter.

So we set up our equation:

6x + 6x + x + x ≤ 147

(x being the width, and 6x being the length, which is 6 times the width)

this simplifies to:

14x ≤ 147

simplify:

x ≤ 10.5

So the width of the fencing is 10.5 feet long, meaning that the length is 63 feet long.

Check answers:

6(10.5) + 6(10.5) + 10.5 + 10.5 = 147

63 + 63 + 21 = 147

126 + 21 = 147

147 = 147

It works, so that is the solution.

Hope this helped :)

Answer 2

length = 63 ft; width = 10.5 ft

Explanation:

Let the width be x.

The length is 6 times the width, so the length is 6x.

The perimeter is the sum of 2 lengths and 2 widths.

6x + 6x + x + x

The perimeter equals 147 ft.

6x + 6x + x + x = 147

14x = 147

x = 10.5

The width is 10.5 ft.

The length is 6x, so the length is 6 * 10.5 ft = 63 ft