172k views
5 votes
Anyone can help me on this Measures of equation practice with angles???​

Anyone can help me on this Measures of equation practice with angles???​-example-1
User Shou
by
7.7k points

2 Answers

3 votes

Answer:

∠B = 45

Explanation:

From the diagram, we can see that ∠A and ∠B are alternate exterior angles. This means ∠B equals ∠A.

We can solve for ∠B by solving for x, then plugging it into ∠B.

we know ∠B = ∠A, so we can write the equation like:

5x-15 = 2x+21

now lets solve for x:

5x - 15 = 2x + 21

Step 1: Subtract 2x from both sides.

5x − 15 − 2x = 2x + 21 − 2x

3x − 15 = 21

Step 2: Add 15 to both sides.

3x − 15 + 15 = 21 + 15

3x = 36

Step 3: Divide both sides by 3.

3x/3 = 36/3

x=12

Now that we know x = 12, we can solve for ∠B

∠B = 2x + 21

∠B = 2(12) + 21

∠B = 45

Anyone can help me on this Measures of equation practice with angles???​-example-1
User Linusg
by
8.4k points
7 votes
Get x by itself the best way is to draw on the left side of the equation then subtract 21 on both sides than divide both sides, x should be by itself then you got the x portion.

x=10.5

And i can’t really help with the angle part but id say somewhere around 45 degrees sorry
User Dyin
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.