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Anyone can help me on this Measures of equation practice with angles???​

Anyone can help me on this Measures of equation practice with angles???​-example-1
User Shou
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2 Answers

3 votes

Answer:

∠B = 45

Explanation:

From the diagram, we can see that ∠A and ∠B are alternate exterior angles. This means ∠B equals ∠A.

We can solve for ∠B by solving for x, then plugging it into ∠B.

we know ∠B = ∠A, so we can write the equation like:

5x-15 = 2x+21

now lets solve for x:

5x - 15 = 2x + 21

Step 1: Subtract 2x from both sides.

5x − 15 − 2x = 2x + 21 − 2x

3x − 15 = 21

Step 2: Add 15 to both sides.

3x − 15 + 15 = 21 + 15

3x = 36

Step 3: Divide both sides by 3.

3x/3 = 36/3

x=12

Now that we know x = 12, we can solve for ∠B

∠B = 2x + 21

∠B = 2(12) + 21

∠B = 45

Anyone can help me on this Measures of equation practice with angles???​-example-1
User Linusg
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5.9k points
7 votes
Get x by itself the best way is to draw on the left side of the equation then subtract 21 on both sides than divide both sides, x should be by itself then you got the x portion.

x=10.5

And i can’t really help with the angle part but id say somewhere around 45 degrees sorry
User Dyin
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5.4k points