Answer:
TRUE
Step-by-step explanation:
As we know that position of minimum intensity on the screen at a given angle of the screen is given by equation
![a sin\theta = N\lambda](https://img.qammunity.org/2020/formulas/physics/college/3twie9mh1xlfzheudckjv9qq0dtfht0x34.png)
now for width of central maximum we will find the angular width of first minimum
![\beta = (2\lambda)/(a)](https://img.qammunity.org/2020/formulas/physics/high-school/6cyj6rlyahoectl29q9zksl27gi09ivybe.png)
now linear width of the central bright fringe is given as
![w = L \beta](https://img.qammunity.org/2020/formulas/physics/high-school/cmnx5pme7harcmsdov4lkrm3zbam0ln7xm.png)
![w = (2\lambda L)/(a)](https://img.qammunity.org/2020/formulas/physics/high-school/evrf5b2nm3e9a90ch1b9vqmpwhdq7akwet.png)
so we can say that if width of the central fringe will decrease by increasing the width of the slit as they as inversely dependent on each other
So its TRUE