1 Answer

Manat · Answer 1 · 2020-12-24T19:26:25+0000

Answer : The radius of a barium atom in angstroms is,
$2.22\AA$

Explanation :

The conversion used for radius from meter to angstroms is:

$(1m=1* 10^(10)\AA)$

As we are given the radius of a barium atom in meter (m) is,
2.22* 10^(-10)m

Now we have to determine the radius of a barium atom in angstrom.

As,
$1m=1* 10^(10)\AA$

So,
$2.22* 10^(-10)m=(2.22* 10^(-10)m)/(1m)* (1* 10^(10)\AA)=2.22\AA$

Therefore, the radius of a barium atom in angstroms is,
$2.22\AA$

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