Question

A circular loop of radius 11.7 cm is placed in a uniform magnetic field. (a) If the field is directed perpendicular to the plane of the loop and the magnetic flux through the loop is 8.60 10-3 T · m2, what is the strength of the magnetic field?

Answer 1

Magnetic field, B = 0.199 T

Step-by-step explanation:

It is given that,

Radius of circular loop, r = 11.7 cm = 0.117 m

Magnetic flux through the loop,
`\phi=8.6* 10^(-3)\ T/m^2`

The magnetic flux linked through the loop is :

`\phi=B.A`

`\phi=BA\ cos\theta`

Here,
`\theta=0`

`B=(\phi)/(A)`

or

`B=(\phi)/(\pi r^2)`

`B=(8.6* 10^(-3))/(\pi (0.117 )^2)`

B = 0.199 T

So, the strength of the magnetic field is 0.199 T. Hence, this is the required solution.