A circular loop of radius 11.7 cm is placed in a uniform magnetic field. (a) If the field is directed perpendicular to the plane of the loop and the magnetic flux through the lo…

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asked Jun 5, 2020 158k views

1 Answer

Argentpepper · Answer 1 · 2020-06-10T12:47:52+0000

Answer:

Magnetic field, B = 0.199 T

Step-by-step explanation:

It is given that,

Radius of circular loop, r = 11.7 cm = 0.117 m

Magnetic flux through the loop,
$\phi=8.6* 10^(-3)\ T/m^2$

The magnetic flux linked through the loop is :

$\phi=B.A$

$\phi=BA\ cos\theta$

Here,
$\theta=0$

$B=(\phi)/(A)$

or

$B=(\phi)/(\pi r^2)$

$B=(8.6* 10^(-3))/(\pi (0.117 )^2)$

B = 0.199 T

So, the strength of the magnetic field is 0.199 T. Hence, this is the required solution.