Answer: 0.5625
Explanation:
Given : The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 8 minutes.
The density function for uniform distribution :-
![f(x)=(1)/(8-0)=(1)/(8)](https://img.qammunity.org/2020/formulas/mathematics/college/6cnelzfw1k2kjvjx8wh96r6sdkgr7g06p3.png)
The required interval : (3.25,8)=8-3.5=4.5
The probability that a randomly selected passenger has a waiting time greater than 3.25 minutes is given by :-
![=(4.5)/(3.25)=0.5625](https://img.qammunity.org/2020/formulas/mathematics/college/vn1x7smlotwphi6wroenkpodl3pzr5lhcr.png)
Hence, the probability that a randomly selected passenger has a waiting time greater than 3.25 minutes