Question

In quadrilateral ABCD m < A= 90°

m 2 C = 50° and m < B = m D.
Find the degree measure of < B.

Answer 1

m∠B = 170°

Explanation:

Sum of all angles in quadrilateral is 360°:

m∠A + m∠B + m∠C + m∠D = 360°

m∠B = 360° - m∠A - m∠C - m∠D

m∠A = 90°

m∠B = m∠D= 50°

m∠B = 360° - 90° - 50° - 50° = 170°