Question

Help pleaseeee! ASAP!

Answer 1

C

Explanation:

First we simplify what we can in the expressions. 3sqrt(3y) can't be so we leave that. We want to try and get everythig to have sqrt(3y) in it though.

sqrt(27y^5) = sqrt((3^3)y^2y^3) = sqrt(3^2y^4*3y) = 3y^2*sqrt(3y)

y^2*sqrt(75y) = y^2*sqrt(5^2*3y) = 5y^2*sqrt(3y)

So now we have 3sqrt(3y) - 3y^2*sqrt(3y) + 5y^2*sqrt(3y)

If we factor out sqrt(3y) we get (3-3y^2+5y^2)sqrt(3y) = (3+2y^2)sqrt(3y) So that's C

Let me know if you don't get how I did something though and I'll be happy to explain it.

Answer 2

Answer : The correct option is, (C)
`√(3y)(3+2y^2)`

Step-by-step explanation :

The given expression is:

`3√(3y)-√(27y^5)+y^2√(75y)`

First we have to break into factors.

`3√(3y)-√(3^3y^5)+y^2√(5^2* 3y)`

Now we have to make the power in even numbers.

`3√(3y)-√(3^2y^4(3y))+y^2√(5^2* 3y)`

`3√(3y)-3y^2√(3y)+5y^2√(3y)`

Now we have to take common
`√(3y)` from the given expression, we get:

`√(3y)(3-3y^2+5y^2)`

Now we have to add like terms, we get:

`√(3y)(3+2y^2)`

Therefore, the correct option is, (C)
`√(3y)(3+2y^2)`