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Calculate the volume of 8.87×10-2 M calcium hydroxide required to neutralize 15.0 mL of a 0.389 M hydrobromic acid solution. mL

1 Answer

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Answer : The volume of calcium hydroxide is, 32.89 ml

Explanation :

Using neutralization law,


n_1M_1V_1=n_2M_2V_2

where,


n_1 = basicity of an acid = 1


n_2 = acidity of a base = 2


M_1 = concentration of hydrobromic acid = 0.389 M


M_2 = concentration of calcium hydroxide = 0.0887 M


V_1 = volume of hydrobromic acid = 15 ml


V_2 = volume of calcium hydroxide = ?

Now put all the given values in the above law, we get the volume of calcium hydroxide.


1* 0.389M* 15ml=2* 0.0887M* V_2


V_2=32.89ml

Therefore, the volume of calcium hydroxide is, 32.89 ml

User Gabriel Brito
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