Question

Calculate the volume of 8.87×10-2 M calcium hydroxide required to neutralize 15.0 mL of a 0.389 M hydrobromic acid solution. mL

Answer 1

Answer : The volume of calcium hydroxide is, 32.89 ml

Explanation :

Using neutralization law,

`n_1M_1V_1=n_2M_2V_2`

where,

`n_1` = basicity of an acid = 1

`n_2` = acidity of a base = 2

`M_1` = concentration of hydrobromic acid = 0.389 M

`M_2` = concentration of calcium hydroxide = 0.0887 M

`V_1` = volume of hydrobromic acid = 15 ml

`V_2` = volume of calcium hydroxide = ?

Now put all the given values in the above law, we get the volume of calcium hydroxide.

`1* 0.389M* 15ml=2* 0.0887M* V_2`

`V_2=32.89ml`

Therefore, the volume of calcium hydroxide is, 32.89 ml