Answer:
![f ^(-1) (8) = (3)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/da093o8gcwenupyxxnsza97mnf3ex2wmy5.png)
Explanation:
We know the function
![f(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/g5as8f90m6mrh9dvzpro2yb3z0msz95zff.png)
![f (x) = 2x +5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3e34sf660tmn6hea02b622cajx2qok9w7q.png)
We want to find
![f ^(-1) (8)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/95jvv7qywmop14qmbvbb3b36q1vc3xz2om.png)
Remember that if we have a function
and its inverse
, then the domain of the function
will be the range of the function
.
This means that to find
we must look for:
![f (x) = 2x +5 = 8](https://img.qammunity.org/2020/formulas/mathematics/middle-school/87kf2uvivt3kr50lfni77623b8rqpblfbo.png)
We solve the equation for x.
![2x + 5 = 8\\\\2x = 8-5\\\\2x = 3\\\\x = (3)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/zi3ygtad5ij0utn98h6wznofqvn193o3m3.png)
So:
![f ^(-1) (8) = (3)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/da093o8gcwenupyxxnsza97mnf3ex2wmy5.png)