Question

P(A)=7/20,P(B)=3/5,P(A∩B)=21/100 ,P(A∪B)=?

Answer 1

P( A U B) = 37/50

Explanation:

7/20+3/5+21/100

IF YOU NEED MORE HELP LMK

Answer 2

Answer: The required value of P(A∪B) is
`(37)/(50).`

Step-by-step explanation: For the two event A and B, we have the following probabilities :

`P(A)=(7)/(20),~~P(B)=(3)/(5),~~P(A\cap B)=(21)/(100).`

We are to find the following probability :

`P(A\cup B)=?`

From the laws of probability, we have

`P(A\cup B)\\\\=P(A)+P(B)-P(A\cap B)\\\\=(7)/(20)+(3)/(5)-(21)/(100)\\\\\\=(35+60-21)/(100)\\\\\\=(74)/(100)\\\\\\=(37)/(50).`

Thus, the required value of P(A∪B) is
`(37)/(50).`