Question

A charge of 1.5 µC is placed on the plates of a parallel plate capacitor. The change in voltage across the plates is 36 V. How much potential energy is stored in the capacitor? × 10–5 J

Answer 1

2.7

Step-by-step explanation:

Answer 2

Energy stored in the capacitor is
`U=2.7* 10^(-5)\ J`

Step-by-step explanation:

It is given that,

Charge,
`q=1.5\ \mu C=1.5* 10^(-6)\ C`

Potential difference, V = 36 V

We need to find the potential energy is stored in the capacitor. The stored potential energy is given by :

`U=(1)/(2)q* V`

`U=(1)/(2)* 1.5* 10^(-6)* 36`

U = 0.000027 J

`U=2.7* 10^(-5)\ J`

So, the potential energy is stored in the capacitor is
`U=2.7* 10^(-5)\ J`. Hence, this is the required solution.