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If $4200 is invested in a savings account for which interest is compounded

semiannually, and if the $4200 turns into $4900 in 4 years, what is the interest
rate of the savings account?

User JEricaM
by
5.3k points

1 Answer

2 votes

Answer:

3.9%

Explanation:

The formula for compound interest to apply is;


A=P(1+(r)/(n) )^(nt)

where;

A=amount at the end

P=starting amount/principal

n=number of compounding years

t=total number of years

r=interest rate expressed as a decimal

Given

P=$4200, n=2, t=4 and A=$4900 R=?

Substitute values in equation, take r=r


A=P(1+(r)/(n) )^(nt) \\\\\\4900=4200(1+(r)/(2) )^(2*4) \\\\\\4900=4200(1+0.5r)^8

Divide both sides by 4200


(4900)/(4200) =(4200)/(4200) (1+0.5r)^8\\\\\\1.1667=(1+0.5r)^8

Introduce root 8 to the left hand side, thus eliminating the power 8 in the right hand side


\sqrt[8]{1.1667} =1+0.5r\\\\\\1.0195=1+0.5r\\\\\\1.0195-1=0.5r\\\\\\0.0195=0.5r\\\\\\(0.0195)/(0.5) =(0.5r)/(0.5) \\\\\\0.039=r

r=3.9%

User Matthew Cline
by
5.7k points