Final answer:
To calculate the current flow in each load resistor, the phase voltage is determined by dividing the secondary phase to phase voltage by the square root of 3 and then applying Ohm's Law with the resistance of 50 ohms, which results in a current of approximately 5.54 A per resistor.
Step-by-step explanation:
The student asked about the current flow in each load resistor of a wye-connected three-phase resistive load associated with a wye-delta transformer with a turns ratio of 2:1 and a secondary phase to phase voltage of 480 V. To find the current in each resistor, we can use Ohm's Law, which states that current (I) equals voltage (V) divided by resistance (R). In a wye-connected system, the phase voltage is the line voltage (VLL) divided by the square root of 3. Therefore, the phase voltage (VL-N) is 480 V divided by √3, which is approximately 277.13 V. Using Ohm's Law (I = V/R), the current in each 50 ohm resistor would be 277.13 V / 50 Ω, giving us approximately 5.54 A. This is the current flow in each load resistor.