Question

A 350 −Ω resistor and a 6.40 −μF capacitor are connected in parallel to an ac generator that supplies an rms voltage of 220 V at an angular frequency of 360 rad/s . Note that since there is no inductor in the circuit, the 1/ωL term is not present in the expression for Z. Find the current amplitude in the resistor..

Answer 1

The current amplitude in the resistor is 0.889 A.

Step-by-step explanation:

Given that,

Resistor
`R= 350\ \Omega`

Capacitor
`C=6.40\ \mu F`

Voltage
`V_(rms) = 220 V`

Frequency = 360 rad/s

We need to calculate the current amplitude in the resistor

Using formula of current amplitude

`I_(max)=(V_(max))/(R)`

`I_(max)=(V_(rms)√(2))/(R)`

Put the value into the formula

`I_(max)=(220√(2))/(350)`

`I_(max)=0.889\ A`

Hence, The current amplitude in the resistor is 0.889 A.