Answer:
The given function is
h(x)=-5x²+60x-200
Let, h(x)=y
![y=-5* (x^2-12 x+40)\\\\ (y)/(-5)=(x-6)^2-36+40\\\\ (-y)/(5)-4=(x-6)^2\\\\y+20=-5(x-6)^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wyx4xsf0ggp86lkbr9az9ylm6rh2zuk7pm.png)
→The Vertex of the Parabola can be obtained by
x-6=0→x=6
And, y+20=0→y=-20
Vertex= (6,-20)
→Drawn the graph of Line, x=-6.
As,well as drawn the graph of , f(x)=x².
h'(x)=-10x+60
-10x+60=0
x=6
h"(x)=-10
Means Function attains maximum at , x=6.
→f(0)=-5×0²+60×0-200
= -200
→So, The value of k, when the equation is written in vertex form, is not -200.it will be , y= -20.
Correct Options are
B.→The graph of h(x) will not intersect the graph of the parent function, f(x) =x².
C.→ The vertex of the graph is at (6, -20).
D.→The parabola has a maximum.