Answer:
The given function is
h(x)=-5x²+60x-200
Let, h(x)=y
→The Vertex of the Parabola can be obtained by
x-6=0→x=6
And, y+20=0→y=-20
Vertex= (6,-20)
→Drawn the graph of Line, x=-6.
As,well as drawn the graph of , f(x)=x².
h'(x)=-10x+60
-10x+60=0
x=6
h"(x)=-10
Means Function attains maximum at , x=6.
→f(0)=-5×0²+60×0-200
= -200
→So, The value of k, when the equation is written in vertex form, is not -200.it will be , y= -20.
Correct Options are
B.→The graph of h(x) will not intersect the graph of the parent function, f(x) =x².
C.→ The vertex of the graph is at (6, -20).
D.→The parabola has a maximum.