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5 votes
Factor the binomial or identify it as prime.

2z4 – 2

A. 2(z2 + 1)(z2 – 1)
B. 2(z2 + 1)(z – 1)(z + 1)
C. Prime
D. 2(z2 + 1)2

Factor the binomial or identify it as prime. 2z4 – 2 A. 2(z2 + 1)(z2 – 1) B. 2(z2 + 1)(z-example-1
User Outofmind
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2 Answers

3 votes
the answer to this problem is A
:)
User Lavonda
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0 votes

Answer:

The correct answer is B,

Explanation:

Since the higher value of z's power, is 4, an even number, and the second number is negative, we can think that this binomial is made of a difference of squares, so that is what we are going to factorize.

First, extract the common number (if any), the number 2, we have now>


2*(z^(4)-1)

This is convenient since "1" is a wonderful number that has this feature>
1^(n)= 1 No matters what n's value is,

so the first equation
2*(z^(4)-1) can be written as
(2*(z^(4)-1)=2*((z^(2))^(2)-1^(2))=2*(z^(2)-1)*(z^(2)+1)

The later termn, can also be factorized, using the same as befre.


(z^(2)-1)=(z-1)*(z+1)

Remember that
z^(4)=(z^(2))^(2)

User Valeh Hajiyev
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