Answer: There are 70 houses that have exactly two of these amenities.
Explanation:
Number of house in a certain development = 150
Number of houses have air conditioning n(A)=
![0.6* 150=90](https://img.qammunity.org/2020/formulas/mathematics/high-school/5rkilsd1rrw8eg6rtgj7gf4q2fo18g6xgg.png)
Number of houses have sunporch n(B) =
![0.5* 150=75](https://img.qammunity.org/2020/formulas/mathematics/high-school/ghnotvq99i6uep5qs1zfqowilf6hj1as6h.png)
Number of houses have swimming pool n(C) =
![0.3* 150=45](https://img.qammunity.org/2020/formulas/mathematics/high-school/3h8y8bc1orbc711ixxl49lfm7yjg5qu8z0.png)
Number of houses have all three amenities = 5
Number of houses have none of them = 5
So, remaining houses = 150-5=145
As we know the rule of sets:
![n(A\cup B\cup C)=n(A)+n(B)+n(C)-n(A\cap B)-n(B\cap C)-n(C\cap A)+n(A\cap B\cap C)\\\\145=90+75+45-n(A\cap B)-n(B\cap C)-n(C\cap A)+5\\\\145=215-n(A\cap B)-n(B\cap C)-n(C\cap A)\\\\145-215=-n(A\cap B)-n(B\cap C)-n(C\cap A)\\\\-70=-n(A\cap B)-n(B\cap C)-n(C\cap A)\\\\n(A\cap B)+n(B\cap C)+n(C\cap A)=70](https://img.qammunity.org/2020/formulas/mathematics/high-school/dd2c8jgbz27fvx2iwzivdm7acdgy8z0kfj.png)
Hence, there are 70 houses that have exactly two of these amenities.