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At some instant and location, the electric field associated with an electromagnetic wave in vacuum has the strength 98.5 V/m. Find the magnetic field strength, the energy density, and the power flow per unit area, all at the same instant and location.

1 Answer

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Answer:


B = 3.28 * 10^(-7) T


u_(density) = 4.3 * 10^(-8) J/m^3


Intensity = 12.88 W/m^2

Step-by-step explanation:

As we know that the electric field strength in vacuum due to electromagnetic waves is given as


E = 98.5 V/m

now we know the relation between electric field and magnetic field as


B = (E)/(c)


B = (98.5)/(3* 10^8)


B = 3.28 * 10^(-7) T

For energy density we know that


u_(density) = (1)/(2)\epsilon_0 E^2


u_(density) = (1)/(2)(8.85 * 10^(-12))(98.5)^2


u_(density) = 4.3 * 10^(-8) J/m^3

Power flow per unit area is given as


Intensity = energy density * speed


Intensity = (4.3 * 10^(-8))(3* 10^8)


Intensity = 12.88 W/m^2

User Dave Delay
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