Question

THIS IS FACTOR GROUPING Help Please

Factor completely x3 − 2x2 − 8x + 16.

(x + 2)(x2 + 8)
(x − 2)(x2 + 8)
(x + 2)(x2 − 8)
(x − 2)(x2 − 8)

Answer 1

(x − 2)(x2 − 8)/ D

Step- by- step explanation:

I'm just going to write the steps.

x3 - 2x2 - 8x + 16

(x3 - 2x2)( - 8x +16)

GCF: x2 GCF: -8

x2(x-2) - 8(x-2)

( x2-8) ( x-2)

Hope this helps!

Answer 2

Answer: D) (x - 2)(x² - 8)

Explanation:

Separate the polynomial into two groups of two terms and factor out the common value from each group. If the values factored out from each group are the same, then you can use the grouping method. The factors will be the outside terms and the common factor.

x³ - 2x² + -8x + 16

= x²(x - 2) + -8(x - 2)

= (x² - 8)(x - 2)