Question

The school cafeteria sells two types of wraps vegetarian and chicken the vegetarian wrap costs $1.00 and the chicken wrap costs $3.40 today they made $266.20 from the 103 wraps sold how many wraps sold were vegetarian

Answer 1

• The school cafeteria sold 35 vegetable wraps.

Explanation:

• Let the count of vegetarian wraps be x
• Let the count of chicken wraps be y.

Then for the count we have :

→ count of vegetarian wraps + count of chicken wraps = 103

→ x + y = 103......[Equation (i)]

Then for the cost we have :

→ ❲$1.00 * x❳ + ❲$3.40 * y❳ = $266.20

Dropping the dollar signs we get :

→ ❲1.00 * x❳ + ❲3.40 * y❳ = 266.20

→ x + 3.40y = 266.20.....[Equation (ii)]

Substracting equation (i) from equation (ii) we get :

→ 0 + 2.4y = 163.2

→ 2.4y = 163.2

→ y = 163.2 ÷ 2.4

→ y = 68

Now, subsitute the value of y = 68 in equation (i) we get :

→ x + y = 103

→ x + 68 = 103

→ x = 103 - 68

→ x = 35

• Hence, the school cafeteria sold 35 vegetable wraps.

Answer 2

35

Explanation:

Let's make a system of equations for the vegetarian and chicken wraps; one for the total cost of them and one for the total amount sold.

Vegetarian wraps will be represented by variable v and chicken wraps will be represented by the variable c.

• v + 3.40c = 266.20
• v + c = 103

Subtract these equations.

• 2.40c = 163.20

Divide both sides by 2.40.

• c = 68

Substitute this value for c into the second equation.

• v + (68) = 103

Subtract 68 from both sides.

• v = 35

The number of vegetarian wraps sold amounted to 35 in total.