Answer:
8.67×10⁻⁶ N/m²
Step-by-step explanation:
p = Momentum of a photon
E = Energy of a photon
c = Speed of light
I = Intensity of light
Force = dp/dt
![p=(E)/(c)](https://img.qammunity.org/2020/formulas/physics/college/9148tgh2lydh06cilirl1u4x1wf53xxfao.png)
![\\\Rightarrow F=((dE)/(dt))/(c)](https://img.qammunity.org/2020/formulas/physics/college/ez2qfkzmrob6pamm9e3vbywm4fy77f4uji.png)
As given in question
![F=2((dE)/(dt))/(c)](https://img.qammunity.org/2020/formulas/physics/college/z908ulybmwsp9r3tcbuh7sr1cv3l76yerr.png)
Now F/A = Pressure
![P=(2I)/(c)\\\Rightarrow P=(2* 1300)/(3* 10^(8))\\\Rightarrow P=8.67* 10^(-6)\ N/m^2](https://img.qammunity.org/2020/formulas/physics/college/uz0i1s43tzff7xukgt7imfpzc7j0jkrrdy.png)
∴ Magnitude of the pressure on the sail is 8.67×10⁻⁶ N/m²