Question

Mars rotates on its axis once every 1.02 days (almost the same as Earth does). (a) Find the distance from Mars at which a satellite would remain in one spot over the Martian surface. (Use 6.42 x 10^23 kg for the mass of Mars).

(b) Find the speed of the satellite.

Answer 1

`r= 2.03*10^7m`

V = 1.45x10^3 m/s

Step-by-step explanation:

number of days in sec = 1.02days * 86400s = 88128 s

Mass of Mars is 6.42*10^23 Kg

gravitational constant G = 6.674*10^{-11}

`T^(2) = \frac {4pi^2}{GM} *r^3`

`\frac {88128^2}{(9.22*10^(-13))} = r^3`

`r= 2.03*10^7m`

(b)
`V=(2 \pi*r)/(T)`

`V=((2 \pi(2.03*10^7)))/((88128)) = 1.45x10^3 m/s`

V