Answer:
The probability that a randomly chosen code starts with M and ends with E is 0.05 ....
Explanation:
According to the given statement we have to make five letter code from A, F, E, R, and M without repeating any letter. We have to find that what is probability that a randomly chosen code starts with M and ends with E.
Thus the probability of picking the first letter M = 1/5
After that we require the sequence (not E, not E, not E) which is equal to:
= 3/4 * 2/3* *1/2
= 1/4
Now multiply 1/5 and 1/4
1/5 * 1/4
= 1/20
= 0.05
Therefore the probability that a randomly chosen code starts with M and ends with E is 0.05 ....