Question

What is the percent-by-mass concentration of acetic acid (CH3COOH) in a vinegar solution that contains 51.80 g acetic acid in a 1.000−L solution? The density of this solution is 1.005 g/mL.

Answer 1

Answer : The percent-by-mass concentration of acetic acid is, 5.15 %

Explanation : Given,

Mass of acetic acid = 51.80 g

Density of solution = 1.005 g/ml

Volume of solution = 1.000 L = 1000 ml (1 L = 1000 ml)

First we have to calculate the mass of solution.

`\text{Mass of solution}=\text{Density of solution}* \text{Volume of solution}`

`\text{Mass of solution}=1.005g/ml* 1000ml=1005g`

Now we have to calculate the percent-by-mass concentration of acetic acid.

`\% \text{ by mass of acetic acid}=\frac{\text{Mass of acetic acid}}{\text{Mass of solution}}* 100`

Now put all the given values in this formula, we get:

`\% \text{ by mass of acetic acid}=(51.80g)/(1005g)* 100=5.15\%`

Therefore, the percent-by-mass concentration of acetic acid is, 5.15 %