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The U.S. Air Force requires that pilots have heights between 64푖푛.and 77푖푛.Heights of women are normally distributed with a mean of 63.7푖푛.and a standard deviation of 2.9푖푛.What percent of women meet that height requirement?

User Cooldude
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Answer:

46.02%

Explanation:

Given that the U.S. Air Force requires that pilots have heights between 64.and 77.

Let X be the random variable representing the heights of women

X is normal with mean = 63.7 and std dev =2.9

Prob height lies between 64 and 77 is


P(64<x<77) =P[(64-63.7)/(2.9) <z<(77-63.7)/(2.9)]\\=P(0.10<z<4.59)\\=0.5-0.0398\\=0.4602

Hence 46.02% percent of women meet that height requirement

User Silwar
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