Question

The U.S. Air Force requires that pilots have heights between 64푖푛.and 77푖푛.Heights of women are normally distributed with a mean of 63.7푖푛.and a standard deviation of 2.9푖푛.What percent of women meet that height requirement?

Answer 1

46.02%

Explanation:

Given that the U.S. Air Force requires that pilots have heights between 64.and 77.

Let X be the random variable representing the heights of women

X is normal with mean = 63.7 and std dev =2.9

Prob height lies between 64 and 77 is

`P(64<x<77) =P[(64-63.7)/(2.9) <z<(77-63.7)/(2.9)]\\=P(0.10<z<4.59)\\=0.5-0.0398\\=0.4602`

Hence 46.02% percent of women meet that height requirement