Answer:
![x^2+y^2=25](https://img.qammunity.org/2020/formulas/mathematics/high-school/r3g3yjuafli8ld5r046p68wd6049xsijrz.png)
Explanation:
Recall the following Pythagorean Identity:
![\sin^2(\theta)+\cos^2(\theta)=1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v6z7zh8wnfrk3ifpc3eoknoxev33bgtg1m.png)
Let's solve the x equation for cos(t) and the y equation for sin(t).
After the solve we will plug into our above identity.
x=5cos(t)
Divide both sides by 5:
(x/5)=cos(t)
y=5sin(t)
Divide both sides by 5:
(y/5)=sin(t)
Now we are ready to plug into the identity:
![\sin^2(t)+\cos^2(t)=1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4wdtpqf73m0l6muktt9yia36ufsqwimdyi.png)
![((y)/(5))^2+((x)/(5))^2=1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/110oei3gdioam8oxb30xonpi3jqcfm5ei4.png)
![(x^2)/(5^2)+(y^2)/(5^2)=1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cv2dzq5mmffd2srodbdnyzzikwv03ptok6.png)
Multiply both sides by 5^2:
![x^2+y^2=5^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/6pob71qfn62yi3tjaf8xcsm6n1r2ti9ry4.png)
This is a circle with center (0,0) and radius 5.
All I did to get that was compare our rectangular equation we found to
![(x-h)^2+(y-k)^2=r^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/kmmm139x85fjht54s8zz0668styzp2e6cm.png)
where (h,k) is the center and r is the radius of a circle.