Question

A 2-m^3 rigid tank contains nitrogen gas at 500kPa and 300K. Now the gas is compressed isothermally to a volume of 0.1 m. The work done on the gas during this compression process is: (a) 950 kJ (b) 0 kJ (c) 1610 kJ (d) 2996 kJ (e) 562 kJ

Answer 1

(d) 2996 kJ

Step-by-step explanation:

We have given initial volume
`v_1=2m^3`

initial pressure
`p_1=500\ kPa`

initial temperature
`T_1=300\ K`

we know that during isothermal process the work done is given by

`W=p_1v_1ln(v_2)/(v_1)`

where
`v_2= final\ volume =0.1m^3\ given`

putting all these value in formula of work done

`W=500* 2* ln(0.1)/(2)`

=-2995.8 kJ here negative sign indicates that work is dine on the gas

so wok done =2995.8 kJ