Answer:
2
Explanation:
There are four 11-year olds and x amount of 14-years old.
We are given the average of this group of 11 and 14 year olds is 12.
This gives us the following equation to solve for x:
![(4(11)+x(14))/(4+x)=12](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vz3zs9f0ecfj3ab32izfpw0rd7888ak0xu.png)
Doing some simplifying on the left and writing 12 as 12/1 on the right because I'm going to cross-multiply in the step to follow:
![(44+14x)/(4+x)=(12)/(1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/n9oxgh1nw0q3ca8wxfmo5ss9p2u57dt47o.png)
Cross multiplying:
![1(44+14x)=(4+x)(12)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ydazb4g3qn7jqqicis55znv1517lilzdxg.png)
Distribute:
![44+14x=48+12x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8ystkl74yy68o9oamtwniiywfqpd4whx4q.png)
Subtract 12x on both sides:
![44+2x=48](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dkwhbuthwn4p48c6t2m1d9sbym0e2i618r.png)
Subtract 44 on both sides:
![2x=4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/sai9js8sfkjdpnsqhep45102fvmu9dre8c.png)
Divide both sides by 2:
![x=2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rgwu4x0cp6hdykhfamznd7kqdkp0xgsg9s.png)
There are two 14-year olds.
Let's confirm.
You have four 11 year olds and two 14 years old.
So you have:
11,11,11,11,14,14
We want to find the average of this set of numbers.
You add the numbers and divide by the number of numbers.
![(11+11+11+11+14+14)/(6)=(72)/(6)=12](https://img.qammunity.org/2020/formulas/mathematics/middle-school/22bknllhopkf2q7h3l438m8zuhhehqmea9.png)
This is the average the problem wanted us to obtain so the work we did above is correct.