Answer:
2
Explanation:
There are four 11-year olds and x amount of 14-years old.
We are given the average of this group of 11 and 14 year olds is 12.
This gives us the following equation to solve for x:

Doing some simplifying on the left and writing 12 as 12/1 on the right because I'm going to cross-multiply in the step to follow:

Cross multiplying:

Distribute:

Subtract 12x on both sides:

Subtract 44 on both sides:

Divide both sides by 2:

There are two 14-year olds.
Let's confirm.
You have four 11 year olds and two 14 years old.
So you have:
11,11,11,11,14,14
We want to find the average of this set of numbers.
You add the numbers and divide by the number of numbers.

This is the average the problem wanted us to obtain so the work we did above is correct.