Question

How many moles of H2 and N2 can be formed by the decomposition of 0.261 mol of ammonia, NH3?

Answer 1

The moles of H2 and N2 are as follows respectively, 0.3915mol of H2 and 0.1305 mol of N2.

Answer 2

Answer: The moles of nitrogen and hydrogen gas formed are 0.261 moles and 0.783 moles respectively.

Step-by-step explanation:

We are given:

Moles of ammonia = 0.261 moles

The chemical equation for the decomposition of ammonia follows:

`2NH_3\rightarrow N_2+3H_2`

By Stoichiometry of the reaction:

2 moles of ammonia produces 1 mole of nitrogen gas and 3 moles of hydrogen gas

So, 0.261 moles of ammonia will produce
`(1* 0.261)=0.261` moles of nitrogen gas and
`(3* 0.261)=0.783` moles of hydrogen gas

Hence, the moles of nitrogen and hydrogen gas formed are 0.261 moles and 0.783 moles respectively.