Find the discriminant and the numbers of real roots for this equation: 4x^2+12x+9=0

Question

asked May 18, 2020 30.1k views

2 Answers

Corbett · Answer 1 · 2020-05-23T07:21:19+0000

Answer:

D=0

The quadratic equation has one real root with a multiplicity of 2.

Explanation:

Given a quadratic equation:

ax^2+bx+c=0

You can find the Discriminant with this formula:

D=b^2-4ac

In this case you have the following quadratic equation:

4x^2+12x+9=0

Where:

$a=4\\b=12\\c=9$

Therefore, when you substitute these values into the formula, you get that the discriminant is this:

$D=(12)^2-4(4)(9)\\\\D=0$

Since
D=0 , the quadratic equation has one real root with a multiplicity of 2 .