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Hello I don’t understand how to do this can someone teach me how to do this

Hello I don’t understand how to do this can someone teach me how to do this-example-1

1 Answer

6 votes

Answer:

g(x)=x+2

Explanation:

So pretend the parent function was y=x.

Pretend we take this parent function and it move it right h units and up k units, then the equation becomes y=(x-h)+k. The assumption here was if h and k were positive.

Now if h is negative then it was moved left h units and if k was negative it was moved down k units.

So we have f(x)=x+6 and we want to move this 4 units right.

This effects the x since we are moving it left or right.

So I'm going to write g(x)=(x-4)+6.

We can simplify this:

g(x)=(x-4)+6

g(x)=x-4 +6

g(x)=x+2

Let's see if this actually moved us right 4 units.

Let's pick a point on f(x)=x+6 by choosing and x to plug in:

I choose x=0.

f(0)=0+6=6.

So the point (0,6) is on this line.

If I moved this points right 4 units it becomes (0+4,6)=(4,6).

This should be on our graph for the function above we found if we did it correctly.

Let's check it:

g(4)=4+2

g(4)=6

Guess what? (4,6) is a point on g because g(4)=6.

Let's do another.

Let's choose x=5.

f(5)=5+6=11 means we have the point (5,11) on the graph of f.

If we moved this point 4 units right it becomes (5+4,11)=(9,11).

Let's check to see if this is on g.

g(x)=x+2

g(9)=9+2

g(9)=11 so (9,11) is on g.

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