Question

a jet fighter accelerates at 17.7 m/s^2 increasing its velocity from 119 m/s to 233 m/s how much time does that take

Answer 1

If its acceleration is constant, then it is equal to the jet's average velocity, given by

`a=a_(\rm ave)=(\Delta v)/(\Delta t)`

Then it takes

`17.7(\rm m)/(\mathrm s^2)=(233(\rm m)/(\rm s)-119(\rm m)/(\rm s))/(\Delta t)\implies\Delta t=\boxed{6.44\,\mathrm s}`

Answer 2

The time taken by the jet is 6.44 seconds.

Explanation:

It is given that,

Acceleration of the jet,
`a=17.7\ m/s^2`

Initial velocity of the jet, u = 119 m/s

Final velocity of the jet, v = 233 m/s

Acceleration of an object is given by :

`a=(v-u)/(t)`

`t=(v-u)/(a)`

`t=(233-119)/(17.7)`

t = 6.44 seconds

So, the time taken by the jet is 6.44 seconds. Hence, this is the required solution.