Question

A single conducting loop of wire has an area of 7.26E-2 m2 and a resistance of 117 Ω. Perpendicular to the plane of the loop is a magnetic field of strength 0.289 T. At what rate (in T/s) must this field change if the induced current in the loop is to be 0.367 A?

Answer 1

`(dB)/(dt)` = 591.45 T/s

Step-by-step explanation:

i = induced current in the loop = 0.367 A

R = Resistance of the loop = 117 Ω

E = Induced voltage

Induced voltage is given as

E = i R

E = (0.367) (117)

E = 42.939 volts

`(dB)/(dt)` = rate of change of magnetic field

A = area of loop = 7.26 x 10⁻² m²

Induced emf is given as

`E = A(dB)/(dt)`

`42.939 = (7.26* 10^(-2))(dB)/(dt)`

`(dB)/(dt)` = 591.45 T/s