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g Water use in the summer is normally distributed with a mean of 310.4 million gallons per day and a standard deviation of 40 million gallons per day. City reservoirs have a combined storage capacity of 350 million gallons. The probability that a day requires more water than is stored in city reservoirs is P(X > 350)= 1 - P (Z < b). What is the value of b? Please report your answer in 3 decimal places.

User Gwelter
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Answer: The value of b = 0.99

The probability that a day requires more water than is stored in city reservoirs is 0.161.

Explanation:

Given : Water use in the summer is normally distributed with


\mu=310.4\text{ million gallons per day}

Standard deviation :
\sigma=40 \text{ million gallons per day}

Let x be the combined storage capacity requires by the reservoir on a random day.

Z-score :
(x-\mu)/(\sigma)


z=(350-310.4)/(40)=0.99

The probability that a day requires more water than is stored in city reservoirs is :


P(x>350)=P(z>0.99)=1-P(z<0.99)\\\\=1-0.8389129=0.1610871\approx0.161

Hence, the probability that a day requires more water than is stored in city reservoirs is 0.161

User Yachi
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