Answer:
Part a)
2) > 1) > 3)
Part b)
1) = 2) = 3)
Step-by-step explanation:
Due to charge induction the magnitude of charge on the inner surface of the outer shell is having same charge as that of the small sphere inside but the sign of charge must be opposite.
So here we can say
1)+ 4q, 0
so inner surface has charge - 4q and outer surface charge is +4q
2) -6q , +10q
so inner surface charge is +6q, outer surface charge is +4q
3) +16q , -12q
so inner surface charge is -16q, outer surface charge is +4q
Part a)
situations in which inner surface charge is arranged in decreasing order is given as
2) > 1) > 3)
Part b)
Situations in which outer surface charge is arranged in decreasing order is given as
1) = 2) = 3)