204k views
3 votes
The point slip form of a line that has a slope of 1/4 and passed through the point (3,0) is shown. Y-0=1/4(x-3) what is the equation in slope intercept form

The point slip form of a line that has a slope of 1/4 and passed through the point-example-1
User Preeya
by
7.8k points

2 Answers

1 vote


\bf y-0=\cfrac{1}{4}(x-3)\implies y=\cfrac{1}{4}(x-3)\implies \stackrel{\textit{distributing}}{y=\cfrac{1}{4}x-\cfrac{3}{4}}

User Rahul Choudhary
by
8.6k points
4 votes

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:


y = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

According to the data we have to:


m = \frac {1} {4}

Then, the equation is of the form:


y = \frac {1} {4} x + b

We substitute point (3.0):


0 = \frac {1} {4} (3) + b\\b = - \frac {3} {4}

Finally, the equation is:


y = \frac {1} {4} x- \frac {3} {4}

Answer:

Option B

User Atef
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories