Question

The point slip form of a line that has a slope of 1/4 and passed through the point (3,0) is shown. Y-0=1/4(x-3) what is the equation in slope intercept form

Answer 1

`\bf y-0=\cfrac{1}{4}(x-3)\implies y=\cfrac{1}{4}(x-3)\implies \stackrel{\textit{distributing}}{y=\cfrac{1}{4}x-\cfrac{3}{4}}`

Answer 2

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

`y = mx + b`

Where:

m: It's the slope

b: It is the cut-off point with the y axis

According to the data we have to:

`m = \frac {1} {4}`

Then, the equation is of the form:

`y = \frac {1} {4} x + b`

We substitute point (3.0):

`0 = \frac {1} {4} (3) + b\\b = - \frac {3} {4}`

Finally, the equation is:

`y = \frac {1} {4} x- \frac {3} {4}`

Answer:

Option B